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(x^2)-46x-46=0
a = 1; b = -46; c = -46;
Δ = b2-4ac
Δ = -462-4·1·(-46)
Δ = 2300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2300}=\sqrt{100*23}=\sqrt{100}*\sqrt{23}=10\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-10\sqrt{23}}{2*1}=\frac{46-10\sqrt{23}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+10\sqrt{23}}{2*1}=\frac{46+10\sqrt{23}}{2} $
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